Answer
**Summary of Results:**
1. **Equation of \( v \)**: \( v(x) = -\frac{1}{2-x} - 1 \)
2. **Symmetry Lines of \( v \)**: None
3. **Intercepts of \( v \)**: \( (0, -\frac{3}{2}), (3, 0), (1, -2) \)
4. **Equation of \( w \)**: \( w(x) = -\frac{1}{x} \)
5. **Asymptotes of \( w \)**: \( x = 0 \) (vertical), \( y = 0 \) (horizontal)
6. **Symmetry Lines of \( w \)**: Line \( y = -x \)
7. **Shortest Distance from \( w \) to the Origin**: \( \sqrt{2} \)
Solution
Let's break down the problem step by step.
### 8.12.1 Determine the equation of \( v \) if \( v \) is the reflection of \( g \) in the \( y \)-axis.
The function \( g(x) \) is given by:
\[
g(x) = -\frac{1}{x+2} - 1
\]
To find the reflection of \( g \) in the \( y \)-axis, we replace \( x \) with \( -x \):
\[
v(x) = g(-x) = -\frac{1}{-x+2} - 1
\]
Now, simplifying \( v(x) \):
\[
v(x) = -\frac{1}{2-x} - 1
\]
### 8.12.2 Determine the symmetry lines of \( v \).
To find the symmetry lines of \( v \), we check if \( v(x) \) is even or odd. A function is even if \( v(x) = v(-x) \) and odd if \( v(-x) = -v(x) \).
Calculating \( v(-x) \):
\[
v(-x) = -\frac{1}{2+x} - 1
\]
Now, we check if \( v(-x) = -v(x) \):
\[
-v(x) = \frac{1}{2-x} + 1
\]
Since \( v(-x) \neq -v(x) \) and \( v(x) \neq v(-x) \), the function \( v \) is neither even nor odd. Therefore, there are no symmetry lines.
### 8.12.3 Sketch \( v \) on a new set of axes, clearly indicating the intercepts with the axes and at least one other point.
To find the intercepts:
1. **Y-intercept**: Set \( x = 0 \):
\[
v(0) = -\frac{1}{2} - 1 = -\frac{3}{2}
\]
So, the y-intercept is \( (0, -\frac{3}{2}) \).
2. **X-intercept**: Set \( v(x) = 0 \):
\[
-\frac{1}{2-x} - 1 = 0
\]
Solving for \( x \):
\[
-\frac{1}{2-x} = 1 \implies -1 = 2 - x \implies x = 3
\]
So, the x-intercept is \( (3, 0) \).
3. **Another point**: Let's calculate \( v(1) \):
\[
v(1) = -\frac{1}{2-1} - 1 = -1 - 1 = -2
\]
So, another point is \( (1, -2) \).
### 8.12.4 Sketch and label the symmetry lines of \( v \).
Since there are no symmetry lines, we will only sketch the function \( v \) with the intercepts and the additional point.
### 8.13.1 State the equation of \( w \).
The function \( w \) is obtained by translating \( g \) 2 units to the right and 1 unit up. The transformation can be expressed as:
\[
w(x) = g(x-2) + 1
\]
Calculating \( g(x-2) \):
\[
g(x-2) = -\frac{1}{(x-2)+2} - 1 = -\frac{1}{x} - 1
\]
Thus,
\[
w(x) = -\frac{1}{x} - 1 + 1 = -\frac{1}{x}
\]
### 8.13.2 State the asymptotes of \( w \).
The function \( w(x) = -\frac{1}{x} \) has:
- A vertical asymptote at \( x = 0 \).
- A horizontal asymptote at \( y = 0 \).
### 8.13.3 State the equations of the symmetry lines of \( w \).
The function \( w(x) = -\frac{1}{x} \) is an odd function, so it has symmetry about the origin. Therefore, the symmetry line is:
- The line \( y = -x \).
### 8.13.4 Determine the shortest distance between \( w \) and the origin.
The shortest distance from the origin to the curve \( w(x) = -\frac{1}{x} \) occurs when the distance function is minimized. The distance \( d \) from the origin to a point \( (x, w(x)) \) is given by:
\[
d = \sqrt{x^2 + w(x)^2} = \sqrt{x^2 + \left(-\frac{1}{x}\right)^2} = \sqrt{x^2 + \frac{1}{x^2}}
\]
To minimize \( d \), we can minimize \( d^2 \):
\[
d^2 = x^2 + \frac{1}{x^2}
\]
Taking the derivative and setting it to zero:
\[
\frac{d}{dx}(x^2 + \frac{1}{x^2}) = 2x - \frac{2}{x^3} = 0
\]
Solving for \( x \):
\[
2x^4 = 2 \implies x^4 = 1 \implies x = 1 \text{ (since distance cannot be negative)}
\]
Now substituting \( x = 1 \) back into \( w(x) \):
\[
w(1) = -1
\]
Thus, the point is \( (1, -1) \) and the distance is:
\[
d = \sqrt{1^2 + (-1)^2} = \sqrt{2}
\]
### Summary of Results:
- **Equation of \( v \)**: \( v(x) = -\frac{1}{2-x} - 1 \)
- **Symmetry lines of \( v \)**: None
- **Intercepts of \( v \)**: \( (0, -\frac{3}{2}), (3, 0), (1, -2) \)
- **Equation of \( w \)**: \( w(x) = -\frac{1}{x} \)
- **Asymptotes of \( w \)**: \( x = 0 \) (vertical), \( y = 0 \) (horizontal)
- **Symmetry lines of \( w \)**: Line \( y = -x \)
- **Shortest distance from \( w \) to the origin**: \( \sqrt{2} \)
Reviewed and approved by the UpStudy tutoring team
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