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The surface area of a square pyrami is 480 sq . ft . If the length of the base 12 ft .. what is its slant height?

Ask by Griffiths Crawford. in the United States
Jan 22,2025

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Answer

The slant height of the pyramid is 14 feet.

Solution

To find the **slant height** of the square pyramid, let's break down the given information and apply the relevant formulas. ### Given: - **Total Surface Area (S)** = 480 square feet - **Base Edge Length (b)** = 12 feet ### Components of Surface Area: 1. **Base Area (A₁):** Since the base is a square, \[ A₁ = b^2 = 12^2 = 144 \text{ sq. ft} \] 2. **Lateral Surface Area (A₂):** This comprises four triangular faces. The area of one triangular face is: \[ \text{Area of one triangle} = \frac{1}{2} \times b \times \text{slant height (s)} \] Therefore, for four triangles: \[ A₂ = 4 \times \left(\frac{1}{2} \times 12 \times s\right) = 2 \times 12 \times s = 24s \] ### Total Surface Area: \[ S = A₁ + A₂ = 144 + 24s = 480 \] ### Solving for Slant Height (s): \[ 144 + 24s = 480 \\ 24s = 480 - 144 \\ 24s = 336 \\ s = \frac{336}{24} \\ s = 14 \text{ feet} \] ### **Answer:** The slant height of the pyramid is **14 feet**.

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To find the slant height of the square pyramid, first, note that the surface area (SA) consists of the area of the base plus the areas of the four triangular faces. The area of the base is \( l^2 = 12^2 = 144 \) sq. ft. Therefore, the area of the four triangular faces is \( SA - \text{base area} = 480 - 144 = 336 \) sq. ft. Each triangular face has an area of \( \frac{1}{2} \times \text{base} \times \text{slant height} \), and since there are four faces, we have: \[ 4 \times \frac{1}{2} \times 12 \times \text{slant height} = 336 \] This simplifies to \( 24 \times \text{slant height} = 336 \), leading to a slant height of \( \frac{336}{24} = 14 \) ft. Now you have the slant height: it’s 14 ft! How sharp would that pyramid look towering at that height?

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