The surface area of a square pyrami is 480 sq . ft . If the length of the base 12 ft .. what is its slant height?
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To find the slant height of the square pyramid, first, note that the surface area (SA) consists of the area of the base plus the areas of the four triangular faces. The area of the base is \( l^2 = 12^2 = 144 \) sq. ft. Therefore, the area of the four triangular faces is \( SA - \text{base area} = 480 - 144 = 336 \) sq. ft. Each triangular face has an area of \( \frac{1}{2} \times \text{base} \times \text{slant height} \), and since there are four faces, we have: \[ 4 \times \frac{1}{2} \times 12 \times \text{slant height} = 336 \] This simplifies to \( 24 \times \text{slant height} = 336 \), leading to a slant height of \( \frac{336}{24} = 14 \) ft. Now you have the slant height: it’s 14 ft! How sharp would that pyramid look towering at that height?