Question
When circle P is plotted on a coordinate plane, the equation of the diameter that passes through point Q on the circle is y=4 x+2. Which statement describes the equation of a line that is tangent to circle P at point Q? A. The slope of the tangent line is -4. B. The slope of the tangent line is 1/4. C. The slope of the tangent line is 4. D. The slope of the tangent line is -1/4.
Ask by Hobbs Wade.
Mar 21,2025 20:28
UpStudy AI Solution
Tutor-Verified Answer
Answer
The slope of the tangent line at point Q is -1/4.
Solution
1. Since the diameter passing through point \( Q \) has the equation
\[
y = 4x + 2,
\]
its slope is \( 4 \).
2. The radius drawn from the center of circle \( P \) to \( Q \) lies along this diameter, so the slope of the radius is also \( 4 \).
3. The tangent line at \( Q \) to the circle is perpendicular to the radius at \( Q \). Therefore, its slope is the negative reciprocal of \( 4 \).
4. The negative reciprocal of \( 4 \) is computed as:
\[
-\frac{1}{4}.
\]
5. Thus, the equation of the line tangent to the circle at \( Q \) has a slope of \( -\frac{1}{4} \), which corresponds to option D.
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Simplify this solution Mind Expander
To determine the slope of the tangent line at point Q on circle P, we need to remember that the tangent line at any point on a circle is perpendicular to the radius extending to that point. The given equation of the diameter is y = 4x + 2, which has a slope of 4.
The slope of the radius to point Q is 4, so the slope of the tangent line, being perpendicular, will be the negative reciprocal of 4, which is -1/4.
Therefore, the correct statement is D: The slope of the tangent line is -1/4.
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