Question

\( \sinh (1) \)

Ask by Lawson Hall. in China
Jan 23,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

\(\sinh(1) \approx 1.1752\)

Solution

The hyperbolic sine function, denoted as \(\sinh(x)\), is defined by the following formula: \[ \sinh(x) = \frac{e^{x} - e^{-x}}{2} \] Evaluating \(\sinh(1)\): \[ \sinh(1) = \frac{e^{1} - e^{-1}}{2} = \frac{e - \frac{1}{e}}{2} \] Calculating the numerical value: \[ e \approx 2.718281828459045 \] \[ \sinh(1) \approx \frac{2.718281828459045 - \frac{1}{2.718281828459045}}{2} \approx \frac{2.718281828459045 - 0.36787944117144233}{2} \approx \frac{2.3504023872876027}{2} \approx 1.1752011936438014 \] **Final Result:** \[ \sinh(1) \approx 1.175201194 \]

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Mind Expander

Did you know that the hyperbolic sine function, \( \sinh(x) \), has its roots in the study of hyperbolas? It mirrors the behavior of sine in circular geometry, but here we’re focusing on the hyperbola, which introduces fascinating properties and applications in various fields, including physics and engineering. So, \( \sinh(1) \) isn't just a number; it's part of a larger mathematical story! Now, when calculating \( \sinh(1) \), you can use the definition \( \sinh(x) = \frac{e^x - e^{-x}}{2} \). Plugging in 1 gives you \( \sinh(1) = \frac{e^1 - e^{-1}}{2} \), which simplifies to approximately 0.8687. This calculation is quite handy, especially when you delve into problems involving equations with exponential growth or decay!

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