Calculate the number of moles of calcium chloride, $$ \mathrm{CaCl}_{2} $$, that can be obtained from 25 g of limestone, $$ \mathrm{CaCO}_{3} $$, in the presence of excess hydrogen chloride, $$ \mathrm{HCl} .(\mathrm{Ca}=40, \mathrm{C}=12, \mathrm{O}= $$ $$ 16, \mathrm{H}=1, \mathrm{Cl}=35.5) $$

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To determine the number of moles of calcium chloride ($$\mathrm{CaCl}_2$$) that can be obtained from 25 grams of limestone ($$\mathrm{CaCO}_3$$) reacting with excess hydrogen chloride ($$\mathrm{HCl}$$), follow these steps:

### 1. **Write the Balanced Chemical Equation**

The reaction between calcium carbonate and hydrochloric acid is:

$$
\mathrm{CaCO}_3 + 2\,\mathrm{HCl} \rightarrow \mathrm{CaCl}_2 + \mathrm{H}_2\mathrm{O} + \mathrm{CO}_2
$$

From the equation, **1 mole of $$\mathrm{CaCO}_3$$ yields 1 mole of $$\mathrm{CaCl}_2$$**.

### 2. **Calculate the Molar Masses**

- **Calcium Carbonate ($$\mathrm{CaCO}_3$$)**
  - Ca: 40 g/mol
  - C: 12 g/mol
  - O: 16 g/mol × 3 = 48 g/mol
  - **Total:** $$40 + 12 + 48 = 100$$ g/mol

- **Calcium Chloride ($$\mathrm{CaCl}_2$$)**
  - Ca: 40 g/mol
  - Cl: 35.5 g/mol × 2 = 71 g/mol
  - **Total:** $$40 + 71 = 111$$ g/mol

### 3. **Determine Moles of $$\mathrm{CaCO}_3$$**

$$
\text{Moles of } \mathrm{CaCO}_3 = \frac{\text{Mass}}{\text{Molar Mass}} = \frac{25\,\text{g}}{100\,\text{g/mol}} = 0.25\,\text{mol}
$$

### 4. **Calculate Moles of $$\mathrm{CaCl}_2$$**

From the balanced equation, **1 mole of $$\mathrm{CaCO}_3$$ produces 1 mole of $$\mathrm{CaCl}_2$$**. Therefore:

$$
\text{Moles of } \mathrm{CaCl}_2 = 0.25\,\text{mol}
$$

### **Final Answer**

**0.25 moles of calcium chloride ($$\mathrm{CaCl}_2$$)** can be obtained from 25 grams of limestone.
0.25 moles of calcium chloride ($$\mathrm{CaCl}_2$$) can be obtained from 25 grams of limestone.

Calculate the number of moles of calcium
chloride, , that can be obtained from 25 g
of limestone, , in the presence of excess
hydrogen chloride,

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Calculate the number of moles of calcium chloride, , that can be obtained from 25 g of limestone, , in the presence of excess hydrogen chloride,