\( \begin{array}{l} \text { Do not include spaces anywhere in your answer. }\\ \begin{array}{l} x \times \quad+. \quad \log . \cos . \quad \mathbf{\delta} \\ (5 x+2)(4 x-7)= \end{array} \end{array} \)

To find \( (5x+2)(4x-7) \), we use the distributive property (also known as the FOIL method for binomials). First, multiply the first terms: \( 5x \times 4x = 20x^2 \). Next, the outer terms: \( 5x \times -7 = -35x \). Then, the inner terms: \( 2 \times 4x = 8x \). Finally, the last terms: \( 2 \times -7 = -14 \). Combining these results, we have: \[ 20x^2 + (-35x + 8x) - 14 = 20x^2 - 27x - 14. \] So, the final output is: \[ 20x^2 - 27x - 14. \]