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The cost Cof producing x thousand calculators is given by the equation below. \[ C=-6.8 x^{2}+7795 x+230,000(x \leqslant 150) \] The average cost per calculator is the total cost \( C \) divided by the number of calculators produced. Write a rational expression that gives the average cost per calculator when \( x \) thousand are produced.

Ask by West Parsons. in the United States
Jan 21,2025

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Answer

The average cost per calculator is given by the expression: \[ A = -\frac{6.8x}{1000} + \frac{7795}{1000} + \frac{230}{x} \]

Solution

To find the average cost per calculator when \( x \) thousand calculators are produced, we need to divide the total cost \( C \) by the number of calculators produced. 1. **Identify the total cost \( C \)**: \[ C = -6.8 x^{2} + 7795 x + 230,000 \] 2. **Determine the number of calculators produced**: Since \( x \) is in thousands, the number of calculators produced is \( 1000x \). 3. **Write the expression for average cost per calculator**: The average cost \( A \) can be expressed as: \[ A = \frac{C}{\text{number of calculators}} = \frac{C}{1000x} \] 4. **Substituting \( C \) into the average cost formula**: \[ A = \frac{-6.8 x^{2} + 7795 x + 230,000}{1000x} \] 5. **Simplifying the expression**: We can simplify this expression by dividing each term in the numerator by \( 1000x \): \[ A = \frac{-6.8 x^{2}}{1000x} + \frac{7795 x}{1000x} + \frac{230,000}{1000x} \] This simplifies to: \[ A = -\frac{6.8 x}{1000} + \frac{7795}{1000} + \frac{230,000}{1000x} \] 6. **Final rational expression for average cost**: Thus, the average cost per calculator when \( x \) thousand calculators are produced is: \[ A = -\frac{6.8 x}{1000} + \frac{7795}{1000} + \frac{230}{x} \] This is the rational expression that gives the average cost per calculator.

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To find the average cost per calculator, simply take the total cost \( C \) and divide it by the number of calculators produced, which is \( 1000x \) (since \( x \) is in thousands). Therefore, the average cost \( A \) per calculator can be expressed as: \[ A = \frac{C}{1000x} = \frac{-6.8x^2 + 7795x + 230000}{1000x} \] This rational expression gives you the average cost per calculator when \( x \) thousand calculators are produced. For clarity, you can simplify it as follows: \[ A = \frac{-6.8x + 7795 + \frac{230000}{x}}{1000} \] Now, doesn’t that just take the cake on average cost? To maximize production efficiency, understanding how costs change with different production levels is vital. Every thousand calculators impacts the overall cost, so businesses must keep an eye on that sweet spot to stay profitable! Balancing costs against production can maximize efficiency and profitability.

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