Question
upstudy study bank question image url

9. Are the following lines parallel, perpendicular or neither? a) \( y=3 x+2 \) and \( y=-\frac{1}{3} x+4 \) b) \( y=\frac{1}{2} x-1 \) and \( 2 y-x=2 \) c) \( 3 y-x=9 \) and \( y=3 x-7 \) d) \( 2 y+3 x=8 \) and \( 3 y=2 x+1 \)

Ask by Ryan Lang. in South Africa
Jan 23,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

a) Perpendicular b) Parallel c) Neither d) Perpendicular

Solution

To determine whether each pair of lines is **parallel**, **perpendicular**, or **neither**, we'll analyze their slopes. - **Parallel Lines** have identical slopes. - **Perpendicular Lines** have slopes that are negative reciprocals of each other (i.e., \( m_1 \times m_2 = -1 \)). - If neither condition is met, the lines are **neither** parallel nor perpendicular. Let's examine each pair: --- ### **a) \( y = 3x + 2 \) and \( y = -\frac{1}{3}x + 4 \)** 1. **Identify the slopes:** - **First line:** \( y = 3x + 2 \) has a slope \( m_1 = 3 \). - **Second line:** \( y = -\frac{1}{3}x + 4 \) has a slope \( m_2 = -\frac{1}{3} \). 2. **Check for Parallelism:** - \( m_1 \neq m_2 \) \( \Rightarrow \) Not parallel. 3. **Check for Perpendicularity:** - \( m_1 \times m_2 = 3 \times \left(-\frac{1}{3}\right) = -1 \). - \( m_1 \times m_2 = -1 \) \( \Rightarrow \) Perpendicular. **Answer:** **Perpendicular** --- ### **b) \( y = \frac{1}{2}x - 1 \) and \( 2y - x = 2 \)** 1. **Rearrange the second equation to slope-intercept form \( y = mx + b \):** - \( 2y = x + 2 \) - \( y = \frac{1}{2}x + 1 \) 2. **Identify the slopes:** - **First line:** \( y = \frac{1}{2}x - 1 \) has a slope \( m_1 = \frac{1}{2} \). - **Second line:** \( y = \frac{1}{2}x + 1 \) has a slope \( m_2 = \frac{1}{2} \). 3. **Check for Parallelism:** - \( m_1 = m_2 \) \( \Rightarrow \) Parallel. 4. **Check for Perpendicularity:** - Not applicable since slopes are equal. **Answer:** **Parallel** --- ### **c) \( 3y - x = 9 \) and \( y = 3x - 7 \)** 1. **Rearrange the first equation to slope-intercept form:** - \( 3y = x + 9 \) - \( y = \frac{1}{3}x + 3 \) 2. **Identify the slopes:** - **First line:** \( y = \frac{1}{3}x + 3 \) has a slope \( m_1 = \frac{1}{3} \). - **Second line:** \( y = 3x - 7 \) has a slope \( m_2 = 3 \). 3. **Check for Parallelism:** - \( m_1 \neq m_2 \) \( \Rightarrow \) Not parallel. 4. **Check for Perpendicularity:** - \( m_1 \times m_2 = \frac{1}{3} \times 3 = 1 \neq -1 \) \( \Rightarrow \) Not perpendicular. **Answer:** **Neither** --- ### **d) \( 2y + 3x = 8 \) and \( 3y = 2x + 1 \)** 1. **Rearrange both equations to slope-intercept form:** - **First equation:** \( 2y + 3x = 8 \) - \( 2y = -3x + 8 \) - \( y = -\frac{3}{2}x + 4 \) - **Second equation:** \( 3y = 2x + 1 \) - \( y = \frac{2}{3}x + \frac{1}{3} \) 2. **Identify the slopes:** - **First line:** \( y = -\frac{3}{2}x + 4 \) has a slope \( m_1 = -\frac{3}{2} \). - **Second line:** \( y = \frac{2}{3}x + \frac{1}{3} \) has a slope \( m_2 = \frac{2}{3} \). 3. **Check for Parallelism:** - \( m_1 \neq m_2 \) \( \Rightarrow \) Not parallel. 4. **Check for Perpendicularity:** - \( m_1 \times m_2 = -\frac{3}{2} \times \frac{2}{3} = -1 \). - \( m_1 \times m_2 = -1 \) \( \Rightarrow \) Perpendicular. **Answer:** **Perpendicular** --- ### **Summary of Results:** - **a)** Perpendicular - **b)** Parallel - **c)** Neither - **d)** Perpendicular

Reviewed and approved by the UpStudy tutoring team

error msg
Explain
Simplify this solution

Bonus Knowledge

To determine the relationship between the lines (parallel, perpendicular, or neither), we need to analyze their slopes. a) The slopes of the lines are \(3\) and \(-\frac{1}{3}\). Since the product of these slopes is \(-1\) (which means they are negative reciprocals), the lines are perpendicular. b) The slope of the first line is \(\frac{1}{2}\). To find the slope of the second line, we rewrite it in slope-intercept form: \[ 2y = x + 2 \Rightarrow y = \frac{1}{2}x + 1 \] Both lines have the same slope \(\frac{1}{2}\), which means they are parallel. c) For the line \(3y - x = 9\), we can rewrite it as: \[ y = \frac{1}{3}x + 3 \] So, the slopes of the lines are \(\frac{1}{3}\) and \(3\). The product of these slopes is \(1\), meaning they are neither parallel nor perpendicular. d) For the first line \(2y + 3x = 8\), we rewrite it as: \[ y = -\frac{3}{2}x + 4 \] And the second line \(3y = 2x + 1\) can be rewritten as: \[ y = \frac{2}{3}x + \frac{1}{3} \] Here, the slopes are \(-\frac{3}{2}\) and \(\frac{2}{3}\). Since the product of the slopes is \(-1\), these lines are also perpendicular. In summary: - a) Perpendicular - b) Parallel - c) Neither - d) Perpendicular

Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy