ype your answer What is the domain of the function $$ \mathrm{f}(\mathrm{x}) $$ $$ =\sqrt{x-1} $$ ? (Enter r for all Real numbers.)

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To find the domain of the function $$ f(x) = \sqrt{x - 1} $$, we need to determine the values of $$ x $$ for which the expression under the square root is non-negative, since the square root function is only defined for non-negative values.

The expression under the square root is $$ x - 1 $$. We set up the inequality:

$$
x - 1 \geq 0
$$

Solving this inequality:

$$
x \geq 1
$$

Thus, the domain of the function $$ f(x) = \sqrt{x - 1} $$ is all real numbers $$ x $$ such that $$ x $$ is greater than or equal to 1.

In interval notation, the domain is:

$$
[1, \infty)
$$

If you want to express the domain in terms of real numbers, you can say:

The domain of $$ f(x) $$ is $$ x \in [1, \infty) $$ or $$ x \geq 1 $$.

If you need to enter "r" for all real numbers, that would not be correct in this case, as the function is not defined for all real numbers. The correct answer is that the domain is $$ x \geq 1 $$.
The domain of $$ f(x) = \sqrt{x - 1} $$ is $$ x \geq 1 $$.

ype your answer What is the domain of the function \( \mathrm{f}(\mathrm{x}) \) \( =\sqrt{x-1} \) ? (Enter r for all Real numbers.)

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