1. Lebo sells home-made biscuits at school to earn some pocket Her profit on one packet of biscults is 28. Determine the values for A and B in the following table: $$ \square $$ $$ 1 \quad 3 \quad 5 \quad B^{1} $$ $$ 8 \quad 24 \mathrm{~A}^{4} 96 $$

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To determine the values of $$ A $$ and $$ B $$ in the given table, let's analyze the information step by step.

### Given Information:
- **Profit per packet of biscuits**: 28
- **Table Structure**:
  
  $$
  \begin{array}{cccc}
  \square & 1 & 3 & 5 & B \
  8 & 24 & A^4 & 96 \
  \end{array}
  $$

### Understanding the Table:
It appears that the table represents a relationship between two quantities, likely the number of packets sold ($$ x $$) and the total profit ($$ y $$). Given that each packet yields a profit of 28, we can deduce that:

$$
y = 28x
$$

However, the table provides different values, so let's explore another relationship.

### Identifying the Pattern:
Looking at the provided table:

- When $$ x = 1 $$, $$ y = 8 $$
- When $$ x = 3 $$, $$ y = 24 $$
- When $$ x = 5 $$, $$ y = A^4 $$
- When $$ x = B $$, $$ y = 96 $$

Observing the pattern:
- For $$ x = 1 $$: $$ y = 8 = 8 \times 1 $$
- For $$ x = 3 $$: $$ y = 24 = 8 \times 3 $$
- For $$ x = 5 $$: $$ y = 8 \times 5 = 40 $$ (implying $$ A^4 = 40 $$)
- For $$ y = 96 $$: $$ 96 = 8 \times 12 $$ (implying $$ B = 12 $$)

### Solving for $$ A $$ and $$ B $$:

1. **Finding $$ B $$**:
   $$
   8 \times B = 96 \implies B = \frac{96}{8} = 12
   $$

2. **Finding $$ A $$**:
   $$
   A^4 = 40 \implies A = \sqrt[4]{40} \approx 2.5119
   $$
   For practical purposes, $$ A $$ can be approximated as $$ 2.5 $$.

### Final Values:
- $$ A \approx 2.5 $$
- $$ B = 12 $$

### Completed Table:
$$
\begin{array}{cccc}
1 & 3 & 5 & 12 \
8 & 24 & (2.5)^4 \approx 40 & 96 \
\end{array}
$$

**Therefore, the values are:**
- $$ A = 2.5 $$
- $$ B = 12 $$
$$ A = 2.5 $$ and $$ B = 12 $$.

1. Lebo sells home-made biscuits at school to earn some pocket Her profit on one packet of biscults is 28. Determine the values for A and B in the following table: \( \square \) \( 1 \quad 3 \quad 5 \quad B^{1} \) \( 8 \quad 24 \mathrm{~A}^{4} 96 \)

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