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3. what is the domain of \( \mathrm{f}(\mathrm{x})=\sqrt{4-\lfloor x\rfloor} \) ? \( \begin{array}{llll}\text { a. }[-2,3] & \text { b. }-2 \leq x \leq 3 & \text { c. }-2
Ask by Willis Bartlett. in Ethiopia
Jan 03,2025

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The domain of \( f(x) = \sqrt{4 - \lfloor x \rfloor} \) is \(-2 \leq x \leq 3\).

Solution

To find the domain of the function \( f(x) = \sqrt{4 - \lfloor x \rfloor} \), we need to ensure that the expression inside the square root is non-negative, since the square root function is only defined for non-negative values. 1. **Identify the condition for the square root:** \[ 4 - \lfloor x \rfloor \geq 0 \] This can be rearranged to: \[ \lfloor x \rfloor \leq 4 \] 2. **Understanding the floor function:** The floor function \( \lfloor x \rfloor \) gives the greatest integer less than or equal to \( x \). Therefore, \( \lfloor x \rfloor \) can take integer values. The condition \( \lfloor x \rfloor \leq 4 \) implies that \( \lfloor x \rfloor \) can be any integer less than or equal to 4. 3. **Determine the possible integer values for \( \lfloor x \rfloor \):** The integers that satisfy \( \lfloor x \rfloor \leq 4 \) are: \[ \lfloor x \rfloor = \ldots, -2, -1, 0, 1, 2, 3, 4 \] 4. **Translate these integer values back to \( x \):** - If \( \lfloor x \rfloor = 4 \), then \( 4 \leq x < 5 \). - If \( \lfloor x \rfloor = 3 \), then \( 3 \leq x < 4 \). - If \( \lfloor x \rfloor = 2 \), then \( 2 \leq x < 3 \). - If \( \lfloor x \rfloor = 1 \), then \( 1 \leq x < 2 \). - If \( \lfloor x \rfloor = 0 \), then \( 0 \leq x < 1 \). - If \( \lfloor x \rfloor = -1 \), then \( -1 \leq x < 0 \). - If \( \lfloor x \rfloor = -2 \), then \( -2 \leq x < -1 \). 5. **Combine the intervals:** The combined intervals for \( x \) based on the values of \( \lfloor x \rfloor \) are: \[ [-2, -1) \cup [-1, 0) \cup [0, 1) \cup [1, 2) \cup [2, 3) \cup [3, 4) \cup [4, 5) \] 6. **Determine the overall domain:** The overall domain of \( f(x) \) is: \[ [-2, 5) \] Now, let's analyze the options provided: - a. \([-2,3]\) - b. \(-2 \leq x \leq 3\) - c. \(-2 < x < 3\) - d. all except c The correct answer must include all values from \([-2, 3]\) and also include values up to 5, which means options a and c are not correct. The best option that includes the domain is option b, which is \(-2 \leq x \leq 3\). Thus, the correct answer is: **b. \(-2 \leq x \leq 3\)**.

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To determine the domain of the function \( f(x) = \sqrt{4 - \lfloor x \rfloor} \), we need to ensure that the expression under the square root is non-negative. Thus, we must have: \[ 4 - \lfloor x \rfloor \geq 0 \] This simplifies to: \[ \lfloor x \rfloor \leq 4 \] The greatest integer function \( \lfloor x \rfloor \) takes integer values, so the possible values of \( \lfloor x \rfloor \) can be \( \ldots, -1, 0, 1, 2, 3, 4 \). Hence, \( x \) must be at least \( -2 \) (where \( \lfloor -2 \rfloor = -2 \)), and it can be at most \( 3.999 \) (where \( \lfloor 4 \rfloor = 4 \)). This gives us the domain \( -2 \leq x < 4 \). Now, analyzing the answer choices: - Option (a) is incorrect because it includes the endpoint of 3, but we actually see that \( \lfloor 3 \rfloor = 3 \) keeps it valid. - Option (b) is correct and includes both endpoints. - Option (c) is incorrect because it improperly excludes -2. - Option (d) is also correct since it excludes only option c. Thus, the correct answer is that the domain is \( -2 \leq x < 4 \), making the answer (b) -2 ≤ x < 3 is the option that fits best. So, the selected answer is (b): -2 ≤ x < 3! Here’s an extra sprinkle of fun knowledge: Did you know that the floor function, \( \lfloor x \rfloor \), can be handy when dealing with computer programming? It helps in rounding down to the nearest integer, which can be useful in scenarios like managing array indexes! Additionally, if you're intrigued by more nuanced mathematical functions like the floor function, exploring topics like the ceiling function \( \lceil x \rceil \) or modulus might tantalize your curiosity. Not only do they have unique applications, but they also interconnect beautifully in various mathematical proofs!

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