\#2 i Let \( f(x)=|x|+6 \). Write a function \( g \) whose graph is a translation 5 units left of the graph of \( f \) The translated function is \( g(x)=\square \).
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To translate the graph of the function \( f(x) = |x| + 6 \) 5 units to the left, we need to shift the input \( x \) by adding 5 to it. This means we will replace \( x \) in the function with \( x + 5 \). Thus, the translated function is \( g(x) = |x + 5| + 6 \). Now, you can visualize \( g(x) \) as the familiar "V" shape of the absolute value function, but now it starts at \( x = -5 \) instead of \( x = 0 \), maintaining the vertical stretch and position due to the +6 constant.