Question
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Use a graphing calculator to solve the equation by graphing. If necessary, round to the nearest hundredth. \( x^{3}-9 x^{2}+27 x=20 \)

Ask by Summers Stanley. in the United States
Jan 23,2025

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Tutor-Verified Answer

Answer

The solution to the equation \( x^3 - 9x^2 + 27x = 20 \) is approximately \( x \approx 1.09 \).

Solution

To solve the equation \( x^3 - 9x^2 + 27x = 20 \) using a graphing calculator, we'll follow these steps: 1. **Rearrange the Equation:** First, rewrite the equation in the standard form: \[ x^3 - 9x^2 + 27x - 20 = 0 \] 2. **Graph the Function:** Plot the function \( f(x) = x^3 - 9x^2 + 27x - 20 \) on a graphing calculator. 3. **Identify the Root:** By observing the graph, you'll notice that the function crosses the x-axis between \( x = 1 \) and \( x = 2 \). This indicates there's a real root in this interval. 4. **Narrow Down the Root:** To approximate the root more precisely: - **At \( x = 1.08 \):** \[ f(1.08) \approx -0.0779 \] - **At \( x = 1.09 \):** \[ f(1.09) \approx 0.0322 \] The root lies between \( x = 1.08 \) and \( x = 1.09 \). 5. **Approximate the Root:** Using linear interpolation between these points: \[ x \approx 1.087 \] Rounding to the nearest hundredth: \[ x \approx 1.09 \] **Solution:** The solution to the equation \( x^3 - 9x^2 + 27x = 20 \) is approximately: \[ x \approx 1.09 \]

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The Deep Dive

To solve the equation \( x^{3}-9 x^{2}+27 x-20=0 \) by graphing, first, rearrange it into the standard form \( y = x^{3}-9 x^{2}+27 x - 20 \). Once entered into a graphing calculator, look for the x-values where the graph intersects the x-axis. These points indicate the roots of the equation. You may need to adjust the viewing window to clearly see the intersections. After graphing, you should find the approximate roots, which you can refine using the graph's trace feature or numerical methods. Rounding to the nearest hundredth might give you values such as \( x \approx 3.87 \) and \( x \approx 5.13 \). Make sure to check for any additional roots, possibly even using polynomial division if needed!

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