Question
6. Given the following exponential functions, identify if it is an exponential growth or decay, identify the initial amount, and the rate of growth (as a percent) of the exponential function. Lastly, evaluate the function when \( t=4 \) \( \begin{array}{ll}\text { a) } y=32,000(0.75)^{t} & \text { b) } y=25(1.05)^{t} \\ \text { growth or decay? } & \text { growth or decay? } \\ \text { initial amount: } & \text { initial amount: } \\ \text { rate of growth: } & \text { rate of growth: } \\ \text { Evaluate for } t=4: & \text { Evaluate for }=4:\end{array} \)
Ask by Hamilton Henry. in the United States
Jan 22,2025
Real Tutor Solution
Tutor-Verified Answer
Answer
**a) \( y = 32,000 \times (0.75)^{t} \)**
- **Growth or Decay:** Decay
- **Initial Amount:** 32,000
- **Rate of Decay:** 25%
- **When \( t = 4 \):** 10,156.25
**b) \( y = 25 \times (1.05)^{t} \)**
- **Growth or Decay:** Growth
- **Initial Amount:** 25
- **Rate of Growth:** 5%
- **When \( t = 4 \):** 30.39
Solution
Sure, let's analyze each exponential function step by step.
---
### **a) \( y = 32,000 \times (0.75)^{t} \)**
1. **Growth or Decay?**
- **Decay**
- **Reason:** The base of the exponential function is **0.75**, which is less than **1**. When the base is between **0** and **1**, the function represents exponential decay.
2. **Initial Amount:**
- **\( 32,000 \)**
- **Explanation:** The initial amount is the value of \( y \) when \( t = 0 \):
\[
y(0) = 32,000 \times (0.75)^{0} = 32,000 \times 1 = 32,000
\]
3. **Rate of Growth (Decay):**
- **25% Decay Rate**
- **Calculation:**
\[
\text{Decay Rate} = 1 - 0.75 = 0.25 \text{ or } 25\%
\]
- **Explanation:** Since the base is **0.75**, the quantity decreases by **25%** each time period.
4. **Evaluate for \( t = 4 \):**
- **Calculation:**
\[
y(4) = 32,000 \times (0.75)^{4} = 32,000 \times 0.31640625 = 10,156.25
\]
- **Result:**
\[
y(4) = 10,156.25
\]
---
### **b) \( y = 25 \times (1.05)^{t} \)**
1. **Growth or Decay?**
- **Growth**
- **Reason:** The base of the exponential function is **1.05**, which is greater than **1**. When the base is greater than **1**, the function represents exponential growth.
2. **Initial Amount:**
- **\( 25 \)**
- **Explanation:** The initial amount is the value of \( y \) when \( t = 0 \):
\[
y(0) = 25 \times (1.05)^{0} = 25 \times 1 = 25
\]
3. **Rate of Growth:**
- **5% Growth Rate**
- **Explanation:** The base is **1.05**, indicating a **5%** increase each time period.
4. **Evaluate for \( t = 4 \):**
- **Calculation:**
\[
y(4) = 25 \times (1.05)^{4} = 25 \times 1.21550625 = 30.38765625
\]
- **Result:**
\[
y(4) \approx 30.39
\]
*(Rounded to two decimal places)*
---
### **Summary Table**
| **Function** | **a) \( y = 32,000 \times (0.75)^t \)** | **b) \( y = 25 \times (1.05)^t \)** |
|------------------------|-------------------------------------------|---------------------------------------|
| **Growth or Decay** | Decay | Growth |
| **Initial Amount** | 32,000 | 25 |
| **Rate of Growth** | 25% Decay Rate | 5% Growth Rate |
| **\( y(4) \)** | 10,156.25 | 30.39 |
---
**Note:**
- When dealing with exponential functions:
- **Base \( > 1 \):** Exponential Growth
- **Base \( < 1 \):** Exponential Decay
- The **initial amount** is always the coefficient of the exponential term when \( t = 0 \).
- The **rate of growth or decay** is determined by how much the base deviates from **1**:
- For growth: \( \text{Rate} = (\text{Base} - 1) \times 100\% \)
- For decay: \( \text{Decay Rate} = (1 - \text{Base}) \times 100\% \)
- To **evaluate** the function at a specific time \( t \), substitute the value of \( t \) into the function and compute the result.
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Beyond the Answer
For the function \( y=32,000(0.75)^{t} \), we have exponential decay since the base \( 0.75 \) is less than 1. The initial amount is \( 32,000 \) and the rate of decay is \( 25\% \) (calculated as \( 1 - 0.75 \) multiplied by 100). Evaluating for \( t=4 \) gives us \( y = 32,000(0.75)^{4} \approx 12,656.25 \). For the function \( y=25(1.05)^{t} \), this is exponential growth due to the base \( 1.05 \) being greater than 1. The initial amount is \( 25 \) and the rate of growth is \( 5\% \). Evaluating for \( t=4 \) gives \( y = 25(1.05)^{4} \approx 30.66 \).