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9. A population of \( N=7 \) scores has a mean of \( \mu=13 \). What is the value of \( \Sigma X \) for this population?

Ask by Robbins Crawford. in the United States
Jan 26,2025

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Answer

The sum of all scores (\( \Sigma X \)) is 91.

Solution

To find the sum of all scores (\( \Sigma X \)) in the population, you can use the formula for the mean: \[ \text{Mean} (\mu) = \frac{\Sigma X}{N} \] Where: - \( \mu \) is the mean, - \( \Sigma X \) is the sum of all scores, - \( N \) is the number of scores. Given: - \( \mu = 13 \) - \( N = 7 \) Rearranging the formula to solve for \( \Sigma X \): \[ \Sigma X = \mu \times N = 13 \times 7 = 91 \] **Answer:** The sum of all scores (\( \Sigma X \)) is **91**.

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The Deep Dive

To find the value of \( \Sigma X \) (the sum of all scores) for the population, you can use the formula for mean: \[ \text{Mean} (\mu) = \frac{\Sigma X}{N} \] Rearranging this formula to solve for \( \Sigma X \) gives: \[ \Sigma X = \mu \times N \] Now, plug in the given values: \[ \Sigma X = 13 \times 7 = 91 \] So, the value of \( \Sigma X \) for the population is \( 91 \).

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