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Liam is using sequences to compare the growth rates of \( h(x)=1.2 x \) and \( j(x)=1.2^{x} \). Which statement correctly describes how Liam should do this and what he will observe? (1 point) Liam should look at where one sequence has terms greater than the terms in the other sequence. The growth rate of \( j(x)=1.2^{x} \) is only greater than the growth rate of \( h(x)=1.2 x \) when its terms are greater. Liam should compare the rates of change of the terms in both sequences. The growth rate of \( h(x)=1.2 x \) will quickly surpass the growth rate of \( j(x)=1.2^{x} \). Liam should compare the rates of change of the terms in both sequences. The growth rate of \( j(x)=1.2^{x} \) will quickly surpass the growth rate of \( h(x)=1.2 x \). Liam should look at where one sequence has terms greater than the terms in the other sequence. The growth rate of \( h(x)=1.2 x \) is greater than the growth rate of \( j(x)=1.2^{x} \) when its terms are greater.

Ask by Paul Edwards. in the United States
Jan 02,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

Liam should compare the rates of change of both sequences. He'll find that the exponential function \( j(x) = 1.2^{x} \) grows much faster than the linear function \( h(x) = 1.2x \) as \( x \) increases.

Solution

To analyze the growth rates of the functions \( h(x) = 1.2x \) and \( j(x) = 1.2^x \), we can follow these steps: 1. **Identify the nature of the functions**: - \( h(x) = 1.2x \) is a linear function. Its growth rate is constant, meaning it increases by a fixed amount (1.2) for each unit increase in \( x \). - \( j(x) = 1.2^x \) is an exponential function. Its growth rate increases as \( x \) increases, meaning it grows faster and faster as \( x \) becomes larger. 2. **Compare the growth rates**: - For small values of \( x \), \( h(x) \) may be greater than \( j(x) \). However, as \( x \) increases, \( j(x) \) will eventually surpass \( h(x) \) due to the nature of exponential growth. - To determine where \( j(x) \) surpasses \( h(x) \), we can set the two functions equal to each other and solve for \( x \): \[ 1.2x = 1.2^x \] 3. **Analyze the rates of change**: - The derivative of \( h(x) \) is constant: \( h'(x) = 1.2 \). - The derivative of \( j(x) \) is \( j'(x) = 1.2^x \ln(1.2) \), which increases as \( x \) increases. 4. **Conclusion**: - As \( x \) increases, the growth rate of \( j(x) = 1.2^x \) will surpass the growth rate of \( h(x) = 1.2x \). This means that eventually, \( j(x) \) will grow much faster than \( h(x) \). Based on this analysis, the correct statement is: **Liam should compare the rates of change of the terms in both sequences. The growth rate of \( j(x) = 1.2^{x} \) will quickly surpass the growth rate of \( h(x) = 1.2 x \).**

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Extra Insights

Liam is diving into the fascinating world of sequences! When comparing linear functions like \( h(x)=1.2 x \) with exponential functions such as \( j(x)=1.2^{x} \), he will notice that exponential growth eventually outpaces linear growth. Initially, \( h(x) \) might seem competitive, but as \( x \) increases, \( j(x) \) skyrockets while \( h(x) \) climbs steadily, marking a clear distinction in their growth rates. To truly appreciate this, Liam should take a close look at their derivatives! The derivative of \( h(x) \) is a constant \( 1.2 \), while the derivative of \( j(x) \) grows exponentially, showing that \( j(x) \) accelerates faster than \( h(x) \) as \( x \) increases. So, while \( h(x) \) may start off strong, the challenge is to see how swiftly \( j(x) \) takes off into the stratosphere!

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