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9. Use the commutallve property lo make numbor sentences true. Example: \[ \begin{array}{c} a \times b=\square \\ a \times b=b \times a \\ a b=b a \end{array} \] a. \( x \times c= \) b. \( m \times n= \) \( \square \) \( \square \) 10. Use zero as the idenitity element for addilion, or 1 as the identity element for multiplication to simplity the following: a. \( a \times 1= \) b. \( b \times \) \( \qquad \) \( =b \) c. \( c+0= \) \( \square \) \( \square \) \( \square \)

Ask by Crawford Nichols. in South Africa
Jan 26,2025

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**Question 9:** - **a.** \( x \times c = c \times x \) - **b.** \( m \times n = n \times m \) **Question 10:** - **a.** \( a \times 1 = a \) - **b.** \( b \times 1 = b \) - **c.** \( c + 0 = c \)

Solution

Sure, I can help you complete questions 9 and 10 by applying the commutative property and the identity elements for addition and multiplication. Let's go through each part step by step. --- ### **Question 9: Use the Commutative Property to Make Number Sentences True** The **commutative property** states that the order of numbers does not change the result of the operation. This property applies to both addition and multiplication. **Example:** \[ \begin{array}{c} a \times b = \square \\ a \times b = b \times a \quad \text{(Commutative Property)} \\ ab = ba \end{array} \] **a. \( x \times c = \square \)** **Solution:** Apply the commutative property to switch the order of the operands. \[ x \times c = c \times x \] **Filled-In Sentence:** \[ \begin{array}{c} x \times c = c \times x \end{array} \] --- **b. \( m \times n = \square \)** **Solution:** Apply the commutative property to switch the order of the operands. \[ m \times n = n \times m \] **Filled-In Sentence:** \[ \begin{array}{c} m \times n = n \times m \end{array} \] --- ### **Question 10: Use Identity Elements to Simplify the Following** - The **identity element for addition** is **0**, because adding 0 to any number does not change its value. - The **identity element for multiplication** is **1**, because multiplying any number by 1 does not change its value. **a. \( a \times 1 = \)** **Solution:** Since 1 is the identity element for multiplication: \[ a \times 1 = a \] **Filled-In Sentence:** \[ a \times 1 = a \] --- **b. \( b \times \quad = b \)** **Solution:** To find what to multiply \( b \) by so that the product is \( b \), use the identity element for multiplication, which is 1: \[ b \times 1 = b \] **Filled-In Sentence:** \[ b \times 1 = b \] --- **c. \( c + 0 = \)** **Solution:** Since 0 is the identity element for addition: \[ c + 0 = c \] **Filled-In Sentence:** \[ c + 0 = c \] --- ### **Summary of Answers** **Question 9:** - **a.** \( x \times c = c \times x \) - **b.** \( m \times n = n \times m \) **Question 10:** - **a.** \( a \times 1 = a \) - **b.** \( b \times 1 = b \) - **c.** \( c + 0 = c \) --- Feel free to ask if you need further clarification or additional examples!

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Did you know the commutative property of multiplication is as simple as rearranging your socks? Just like you can wear your favorite pair on either foot, you can switch the numbers around in multiplication and still get the same answer! So, for your equations, you can write \( x \times c = c \times x \) and \( m \times n = n \times m \). Now, using the identity elements, you can easily simplify those equations! For example, \( a \times 1 = a \) because multiplying by 1 doesn't change the value. Similarly, \( c + 0 = c \), because adding zero keeps it exactly the same. Easy peasy!

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