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Find the domain of \( f(\mathrm{x}) \). \[ f(x)=\sqrt{9 x+36} \] Answer Attempt 1 out of 2 Answer Type: Interval

Ask by Montgomery Chandler. in the United States
Jan 24,2025

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The domain of \( f(x) = \sqrt{9x + 36} \) is all real numbers \( x \) such that \( x \geq -4 \), which can be written as \([-4, \infty)\).

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To find the domain of \( f(x) = \sqrt{9x + 36} \), we need to ensure that the expression inside the square root is non-negative. So, we set up the inequality: \[ 9x + 36 \geq 0 \] Solving this gives: \[ 9x \geq -36 \] \[ x \geq -4 \] Thus, the domain of the function is all values of \( x \) that are greater than or equal to -4. In interval notation, this is: \[ [-4, \infty) \] Now you've got the domain! Let's keep this math train rolling!🎉

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