Use the given information to solve right triangle \( A B C \) for all missing parts. \( A=31.5^{\circ}, a=7 \frac{3}{4} \mathrm{in} \). \( B=58.5^{\circ} \) (Type an integer or a decimal.) \( \mathrm{b} \approx 12.6 \) in. (Type an integer or a decimal. Round to the nearest tenth as needed.) \( \mathrm{c} \approx \square \) in. (Type an integer or a decimal. Round to the nearest tenth as needed.)
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The Deep Dive
To find the missing part \( c \) of triangle \( ABC \), we can use the Law of Sines. We already have angles \( A \) and \( B \) and side \( a \). First, let's find angle \( C \): \[ C = 180^\circ - A - B = 180^\circ - 31.5^\circ - 58.5^\circ = 90^\circ \] Now that we know it's a right triangle, we can use the sine function to find side \( c \) using side \( a \): \[ \frac{a}{\sin A} = \frac{c}{\sin C} \] Since \( \sin C = 1 \) (for right angle), we have: \[ c = a \cdot \frac{\sin C}{\sin A} \] Substituting values: \[ c = 7.75 \cdot \frac{1}{\sin(31.5^\circ)} \] Calculating \( \sin(31.5^\circ) \) gives approximately \( 0.524 \): \[ c \approx 7.75 \cdot 1.907 = 14.8 \] Thus, side \( c \approx 14.8 \) in.