Sixty boys and girls divided a sum of $$ \$ 51 $$. If each boy gets 79 cents and each girl gets 139 cents, what is the number of boys and girls in the group?

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Let’s denote:
- $$ b $$ as the number of boys
- $$ g $$ as the number of girls

We are given two main pieces of information:

1. **Total number of children:**
   $$
   b + g = 60
   $$

2. **Total amount of money distributed:**
   Each boy receives \$0.79 and each girl receives \$1.39, summing up to \$51.
   $$
   0.79b + 1.39g = 51
   $$

To eliminate decimals, multiply the second equation by 100:
$$
79b + 139g = 5100
$$

**Substituting $$ b = 60 - g $$ into the equation:**
$$
79(60 - g) + 139g = 5100
$$
$$
4740 - 79g + 139g = 5100
$$
$$
4740 + 60g = 5100
$$
$$
60g = 5100 - 4740
$$
$$
60g = 360
$$
$$
g = \frac{360}{60} = 6
$$

**Finding the number of boys:**
$$
b = 60 - g = 60 - 6 = 54
$$

**Verification:**
- Amount for boys: $$ 54 \times 0.79 = 42.66 $$ dollars
- Amount for girls: $$ 6 \times 1.39 = 8.34 $$ dollars
- Total: $$ 42.66 + 8.34 = 51.00 $$ dollars (matches the given total)

**Conclusion:**
There are **54 boys and 6 girls** in the group.

**Answer:**  
54 boys and 6 girls are in the group.
There are 54 boys and 6 girls in the group.

Sixty boys and girls divided a sum of .
If each boy gets 79 cents and each girl gets 139 cents, what is the number of boys
and girls in the group?

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Sixty boys and girls divided a sum of . If each boy gets 79 cents and each girl gets 139 cents, what is the number of boys and girls in the group?