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Distributive property: Integer coefficients Use the distributive property to remove the parentheses. \( \quad-5\left(-w^{3}+1-3 x^{2}\right) \)

Ask by Peterson Estrada. in the United States
Jan 24,2025

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Tutor-Verified Answer

Answer

\[ 5w^{3} + 15x^{2} - 5 \]

Solution

To remove the parentheses using the distributive property, you need to multiply each term inside the parentheses by \(-5\). Here's how you can do it step by step: \[ -5\left(-w^{3} + 1 - 3x^{2}\right) \] 1. **Distribute \(-5\) to \(-w^3\):** \[ -5 \times (-w^3) = 5w^3 \] 2. **Distribute \(-5\) to \(1\):** \[ -5 \times 1 = -5 \] 3. **Distribute \(-5\) to \(-3x^2\):** \[ -5 \times (-3x^2) = 15x^2 \] 4. **Combine all the terms:** \[ 5w^3 + 15x^2 - 5 \] So, the expression after applying the distributive property is: \[ 5w^{3} + 15x^{2} - 5 \]

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When using the distributive property, you take the coefficient outside the parentheses and multiply it by each term inside. For the expression \(-5(-w^{3}+1-3x^{2})\), you would distribute \(-5\) to each term within the parentheses: \(-5 \times -w^{3} = 5w^{3}\) \(-5 \times 1 = -5\) \(-5 \times -3x^{2} = 15x^{2}\) So, combining these results gives you \(5w^{3} - 5 + 15x^{2}\). Now, did you know that the distributive property isn't just for numbers? It plays a big role in algebra, allowing us to simplify expressions and solve equations. By understanding how to distribute, you're like a math magician, making complicated expressions simpler with just a flick of your pen! Also, a common mistake with the distributive property is forgetting to apply the negative sign correctly. It's like opening a surprise gift only to find out you missed an important part of the wrapping! Always double-check that you're distributing the sign with the coefficient to each term inside the parentheses.

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