Solve the inequality, for \( w \). \( \left.\qquad \begin{array}{l}\square+8+w \leq 13 \\ \text { Simplify your answer as much as possible. } \\ \square\end{array}\right] \quad \square \leq \square \leq \square \)

To solve the inequality \( x + 8 + w \leq 13 \), we first isolate \( w \): 1. Subtract 8 from both sides to simplify: \[ x + w \leq 5 \] 2. Next, isolate \( w \) by subtracting \( x \) from both sides: \[ w \leq 5 - x \] Now, if we consider the additional constraints that are likely present in your inequality (as indicated by "square ≤ square ≤ square"), we can assume we have bounds for \( w \). For example, if we had these constraints: - \( w \geq 0 \) - \( w \leq 5 - x \) Thus, the final results can be combined into a compound inequality such as: \[ 0 \leq w \leq 5 - x \] Make sure to substitute any specific values for \( x \) if they are provided to get more precise limits on \( w \).