(12 marks) single-story factory has a 1.5 MVA, 22kVI45V, ONAN, DYN11 distribution transform provide electricity for the factory. Calculate the current supplying to the factory i) Explain why it is a good choice to use this transformer for this factory (ii) Sketch an annotated showing the windings configuration and voltages for the transformer. Question 3 (10 marks) (a) State the full description of the abbreviation 'RCCB', which is commonly found in

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To calculate the current supplying to the factory, we need to use the formula:

$$ I = \frac{P}{V} $$

where:
- $$ I $$ is the current in amperes (A)
- $$ P $$ is the power in watts (W)
- $$ V $$ is the voltage in volts (V)

Given:
- Power $$ P = 1.5 $$ MVA
- Voltage $$ V = 22 $$ kV

First, we need to convert the power from MVA to watts:
$$ 1.5 \, \text{MVA} = 1.5 \times 10^6 \, \text{VA} $$

Now, we can calculate the current:
$$ I = \frac{1.5 \times 10^6}{22 \times 10^3} $$

Let's calculate the current.
Calculate the value by following steps:
- step0: Calculate:
  $$\frac{1.5\times 10^{6}}{\left(22\times 10^{3}\right)}$$
- step1: Remove the parentheses:
  $$\frac{1.5\times 10^{6}}{22\times 10^{3}}$$
- step2: Factor the expression:
  $$\frac{2\times 750000}{22\times 10^{3}}$$
- step3: Reduce the fraction:
  $$\frac{750000}{11\times 10^{3}}$$
- step4: Factor the expression:
  $$\frac{10000\times 75}{11\times 10^{3}}$$
- step5: Reduce the fraction:
  $$\frac{10\times 75}{11}$$
- step6: Calculate:
  $$\frac{750}{11}$$
The current supplying to the factory is approximately 68.18 A.

Now, let's address the second part of the question:

(i) It is a good choice to use this transformer for this factory because it provides a suitable voltage level for the factory's needs. The transformer is designed to step down the high voltage from the distribution grid to a lower voltage that is suitable for the factory's equipment.

(ii) The windings configuration and voltages for the transformer are as follows:

- Primary windings: 22 kV
- Secondary windings: 4.5 kV

The transformer is a single-phase, three-winding transformer with the primary winding connected to the 22 kV distribution grid and the secondary winding connected to the factory's equipment. The transformer is designed to provide a step-down voltage transformation from 22 kV to 4.5 kV, which is suitable for the factory's needs.

Now, let's address the third part of the question:

(a) The full description of the abbreviation 'RCCB' is:
- R: Residual
- C: Current
- C: Circuit
- B: Breaker

RCCB stands for Residual Current Circuit Breaker, which is a type of electrical safety device that detects and interrupts the flow of electrical current in a circuit. It is designed to protect people and equipment from electrical shock and is commonly found in electrical installations.
The current supplying to the factory is approximately 68.18 A. The transformer is suitable for the factory due to its voltage transformation capabilities. RCCB stands for Residual Current Circuit Breaker, a safety device for electrical installations.

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