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You put \( 20 \% \) down on a home with a purchase price of \( \$ 250,000 \). The down payment is thus \( \$ 50,000 \), leaving a balance owed of \( \$ 200,000 \). The bank will loan the remaining balance at \( 3.91 \% \) APR. You will make annual payments with a 30 - year payment schedule. What is the annual annuity payment under this schedule? A. \( \$ 11,009.49 \) B. \( \$ 6,666.67 \) C. \( \$ 18,100.23 \) D. \( \$ 11,439.96 \)

Ask by George Wade. in the United States
Jan 24,2025

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Tutor-Verified Answer

Answer

The annual annuity payment is approximately \$11,439.96.

Solution

To find the annual annuity payment under the given schedule, we can use the formula for the annual payment of an annuity: \[ A = \frac{P \times r \times (1 + r)^n}{(1 + r)^n - 1} \] where: - \( A \) is the annual payment - \( P \) is the principal amount (the balance owed after the down payment) - \( r \) is the annual interest rate (APR) - \( n \) is the number of years in the payment schedule Given: - Principal amount \( P = \$200,000 \) - Annual interest rate \( r = 3.91\% = 0.0391 \) - Number of years \( n = 30 \) Substitute the values into the formula to find the annual annuity payment. Calculate the value by following steps: - step0: Calculate: \(\frac{200000\times 0.0391\left(1+0.0391\right)^{30}}{\left(\left(1+0.0391\right)^{30}-1\right)}\) - step1: Remove the parentheses: \(\frac{200000\times 0.0391\left(1+0.0391\right)^{30}}{\left(1+0.0391\right)^{30}-1}\) - step2: Add the numbers: \(\frac{200000\times 0.0391\times 1.0391^{30}}{\left(1+0.0391\right)^{30}-1}\) - step3: Add the numbers: \(\frac{200000\times 0.0391\times 1.0391^{30}}{1.0391^{30}-1}\) - step4: Convert the expressions: \(\frac{200000\times 0.0391\left(\frac{10391}{10000}\right)^{30}}{1.0391^{30}-1}\) - step5: Convert the expressions: \(\frac{200000\times 0.0391\left(\frac{10391}{10000}\right)^{30}}{\left(\frac{10391}{10000}\right)^{30}-1}\) - step6: Multiply: \(\frac{7820\times \frac{10391^{30}}{10000^{30}}}{\left(\frac{10391}{10000}\right)^{30}-1}\) - step7: Subtract the numbers: \(\frac{7820\times \frac{10391^{30}}{10000^{30}}}{\frac{10391^{30}-10000^{30}}{10000^{30}}}\) - step8: Evaluate the power: \(\frac{\frac{391\times 10391^{30}}{20^{59}\times 25^{30}}}{\frac{10391^{30}-10000^{30}}{10000^{30}}}\) - step9: Multiply by the reciprocal: \(\frac{391\times 10391^{30}}{20^{59}\times 25^{30}}\times \frac{10000^{30}}{10391^{30}-10000^{30}}\) - step10: Rewrite the expression: \(\frac{391\times 10391^{30}}{20^{59}\times 25^{30}}\times \frac{400^{30}\times 25^{30}}{10391^{30}-10000^{30}}\) - step11: Rewrite the expression: \(\frac{391\times 10391^{30}}{20^{59}\times 25^{30}}\times \frac{20^{60}\times 25^{30}}{10391^{30}-10000^{30}}\) - step12: Reduce the numbers: \(\frac{391\times 10391^{30}}{25^{30}}\times \frac{20\times 25^{30}}{10391^{30}-10000^{30}}\) - step13: Rewrite the expression: \(\frac{391\times 10391^{30}}{25^{30}}\times \frac{5\times 4\times 25^{30}}{10391^{30}-10000^{30}}\) - step14: Rewrite the expression: \(\frac{391\times 10391^{30}}{5^{60}}\times \frac{5\times 4\times 25^{30}}{10391^{30}-10000^{30}}\) - step15: Reduce the numbers: \(\frac{391\times 10391^{30}}{5^{59}}\times \frac{4\times 25^{30}}{10391^{30}-10000^{30}}\) - step16: Rewrite the expression: \(\frac{391\times 10391^{30}}{5^{59}}\times \frac{4\times 5^{60}}{10391^{30}-10000^{30}}\) - step17: Reduce the numbers: \(391\times 10391^{30}\times \frac{4\times 5}{10391^{30}-10000^{30}}\) - step18: Multiply: \(\frac{391\times 10391^{30}\times 20}{10391^{30}-10000^{30}}\) - step19: Multiply: \(\frac{7820\times 10391^{30}}{10391^{30}-10000^{30}}\) The annual annuity payment under the given schedule is approximately \( \$11,439.96 \). Therefore, the correct answer is D. \( \$11,439.96 \).

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The Deep Dive

To calculate the annual annuity payment for a loan of \( 200,000 \) at an APR of \( 3.91\% \) over a 30-year term, we can use the formula for the annual payment \( PMT \) of an annuity: \[ PMT = P \times \frac{r(1+r)^n}{(1+r)^n - 1} \] where: - \( P \) is the loan amount (\( 200,000 \)) - \( r \) is the annual interest rate (0.0391) - \( n \) is the number of payments (30) Plugging in the numbers: \[ PMT = 200,000 \times \frac{0.0391(1+0.0391)^{30}}{(1+0.0391)^{30} - 1} \] Calculating this gives an annual payment of approximately \( 11,009.49 \). Therefore, the correct answer is: A. \( \$ 11,009.49 \) --- Loan payments are just one aspect of managing home ownership. Real-world application of interest rates and amortization is crucial. Many homeowners opt to refinance if rates drop, which can significantly lower monthly payments and save money over the loan term. Knowledge of these operations enables smart financial decisions, potentially leading to substantial savings over time. If you're curious about mortgages, financial calculators are abundant online! You can do a little digging into how changing interest rates might affect your future payments or explore different loan opções, such as fixed vs. adjustable rates. Understanding these aspects can be a game changer in home buying and personal finance management!

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