What is the next fraction in this sequence? \( \frac{2}{89}, \frac{4}{89}, \frac{8}{89}, \frac{16}{89}, \ldots \)

The fractions in the sequence are following a pattern where the numerator doubles with each term, while the denominator remains constant at 89. The numerators are: - 2 (which is \(2^1\)), - 4 (which is \(2^2\)), - 8 (which is \(2^3\)), - 16 (which is \(2^4\)). Thus, the next numerator would be \(2^5 = 32\). Therefore, the next fraction in the sequence is: \(\frac{32}{89}\).