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a) \( 261+0 \) c) \( (0 \times 57)+(0 \div 65) \)

Ask by Vaughn Elliott. in South Africa
Jan 21,2025

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a) \(261 + 0 = 261\) c) \( (0 \times 57) + (0 \div 65) = 0 \)

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Adding zero to a number leaves it unchanged, so \( 261 + 0 = 261 \). It’s like trying to spice up a cooked dish by adding nothing—what remains is the original flavor! Now, for the other expression, any operation involving zero will yield zero results unless it’s division. So, \( (0 \times 57) + (0 \div 65) = 0 + 0 = 0 \). It's a bit like saying, "Hey! If you have zero cookies and no way to divide them, you still have zero cookies!” Keep it simple!

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