2. The cost to buy $$ p $$ pounds of potatoes at $$ \$ 0.32 $$ per pound and $$ n $$ pounds of onions at $$ \$ 0.48 $$ per pound can be determined by using the expression $$ 0.32 p+0.48 n $$. How much will it cost to buy 4.5 pounds of potatoes and 2.5 pounds of onions?

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Para determinar el costo de comprar 4.5 libras de papas y 2.5 libras de cebollas, utilizamos la expresión dada:

$$
\text{Costo} = 0.32p + 0.48n
$$

Donde:
- $$ p = 4.5 $$ libras de papas
- $$ n = 2.5 $$ libras de cebollas

Sustituyendo los valores:

$$
\text{Costo} = 0.32 \times 4.5 + 0.48 \times 2.5
$$

Calculamos cada parte por separado:

1. **Costo de las papas:**
$$
0.32 \times 4.5 = 1.44 \ \text{dólares}
$$

2. **Costo de las cebollas:**
$$
0.48 \times 2.5 = 1.20 \ \text{dólares}
$$

Sumando ambos costos:

$$
1.44 + 1.20 = 2.64 \ \text{dólares}
$$

**Por lo tanto, el costo total para comprar 4.5 libras de papas y 2.5 libras de cebollas es de \$2.64.**
El costo total es \$2.64.

2. The cost to buy \( p \) pounds of potatoes at \( \$ 0.32 \) per pound and \( n \) pounds of onions at \( \$ 0.48 \) per pound can be determined by using the expression \( 0.32 p+0.48 n \). How much will it cost to buy 4.5 pounds of potatoes and 2.5 pounds of onions?

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