ikda 14 ta oq va 5 ta qora shar bor. Tavakkal 6 ta shar olingan. Olingan shar oq shar bo’lish ehtimolini toping.
saning 550 sinovning har birida ro’y berish ehtimoli 0,4 bo’lib, hodisaning ko’pi bilan 250 marta ro’y berish ehtime
g mlari har hil bo’lgan ikki xonali son o’ylandi. Tavakkaliga aytilgan 2 xonali sonlar raqamlari yig’idisi 8 ga karrali so

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Alright, I need to solve this problem step by step. Let's break it down carefully to ensure I understand all the components and relationships involved.

**Given:**
1. There are 14 white balls and 5 black balls in a bag.
2. A person draws 6 balls from the bag.
3. The probability of drawing a white ball is 0.4.
4. The event occurs 250 times.
5. A two-digit number is drawn, and the sum of its digits is a multiple of 8.
6. The probability of an event occurring is 0.4.

**Objective:**
Find the probability that the drawn balls are white.

**Step 1: Understanding the Composition of the Bag**
- Total balls = 14 white + 5 black = 19 balls.

**Step 2: Calculating the Probability of Drawing a White Ball**
- Probability of drawing a white ball (P(White)) = Number of white balls / Total number of balls = 14/19 ≈ 0.7368.

**Step 3: Calculating the Probability of Drawing 6 White Balls**
- This is a hypergeometric probability problem since we're dealing with draws without replacement.
- The formula for hypergeometric probability is:
  
  $$
  P(X = k) = \frac{{\binom{K}{k} \binom{N-K}{n-k}}}{{\binom{N}{n}}}
  $$
  
  Where:
  - $$ N = 19 $$ (total balls)
  - $$ K = 14 $$ (white balls)
  - $$ n = 6 $$ (number of draws)
  - $$ k = 6 $$ (number of white balls drawn)

- Plugging in the numbers:
  
  $$
  P(X = 6) = \frac{{\binom{14}{6} \binom{5}{0}}}{{\binom{19}{6}}}
  $$
  
- Calculating the combinations:
  
  $$
  \binom{14}{6} = 3003
  $$
  
  $$
  \binom{5}{0} = 1
  $$
  
  $$
  \binom{19}{6} = 27132
  $$
  
- Therefore:
  
  $$
  P(X = 6) = \frac{3003 \times 1}{27132} ≈ 0.1107
  $$
  
**Step 4: Considering the Additional Information**
- The problem mentions that the probability of an event occurring is 0.4, and it occurs 250 times.
- It also mentions a two-digit number where the sum of its digits is a multiple of 8.
- However, these details seem unrelated to the primary question of finding the probability of drawing white balls. They might be additional information or part of a larger problem that isn't fully provided.

**Step 5: Final Probability Calculation**
- Based on the hypergeometric calculation, the probability of drawing 6 white balls from the bag is approximately 0.1107 or 11.07%.

**Conclusion:**
The probability that the drawn balls are white is approximately 11.07%.

Вероятность того, что вытащенные шары белые, составляет около 11,07%.

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