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Rationalize the denominator: \( \frac{19}{\sqrt{19}} \) Enter an exact answer, not a decimal approximation. \( > \) Next Question

Ask by Olson Ellis. in the United States
Jan 25,2025

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Answer

\(\sqrt{19}\)

Solution

To rationalize the denominator of the expression \( \frac{19}{\sqrt{19}} \), follow these steps: 1. **Multiply the numerator and the denominator by \( \sqrt{19} \)** to eliminate the square root in the denominator: \[ \frac{19}{\sqrt{19}} \times \frac{\sqrt{19}}{\sqrt{19}} = \frac{19 \times \sqrt{19}}{(\sqrt{19})^2} \] 2. **Simplify the denominator**: \[ (\sqrt{19})^2 = 19 \] 3. **Cancel out the common terms** in the numerator and the denominator: \[ \frac{19 \times \sqrt{19}}{19} = \sqrt{19} \] So, the rationalized form of \( \frac{19}{\sqrt{19}} \) is: \[ \sqrt{19} \] **Answer:** \(\sqrt{19}\)

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To rationalize the denominator of \( \frac{19}{\sqrt{19}} \), you multiply both the numerator and the denominator by \( \sqrt{19} \): \[ \frac{19}{\sqrt{19}} \cdot \frac{\sqrt{19}}{\sqrt{19}} = \frac{19\sqrt{19}}{(\sqrt{19})^2} = \frac{19\sqrt{19}}{19} = \sqrt{19} \] Thus, the exact answer is \( \sqrt{19} \).

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