Question
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\[ \begin{array}{l}y=76 \\ \qquad=x^{2}-5\end{array} \] The graphs of the given equations in the \( x y \)-plane intersat at the point \( (x, y) \). What is a possible value of \( x \) ? \( -\frac{76}{5} \)

Ask by Mcdonald Carlson. in the United States
Jan 23,2025

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Tutor-Verified Answer

Answer

A possible value of \( x \) is \( 9 \) or \( -9 \).

Solution

To find the points of intersection between the two equations: \[ \begin{aligned} y &= 76 \\ y &= x^2 - 5 \end{aligned} \] we can set them equal to each other since they both equal \( y \): \[ 76 = x^2 - 5 \] Solving for \( x \): \[ x^2 = 76 + 5 \\ x^2 = 81 \\ x = \pm \sqrt{81} \\ x = \pm 9 \] **Possible values of \( x \) are \( 9 \) and \( -9 \).** The value \( -\frac{76}{5} \) (which is approximately \(-15.2\)) is **not** a solution to the system of equations. **Conclusion:** A possible value of \( x \) where the graphs intersect is **\( 9 \)** or **\( -9 \)**.

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Extra Insights

To find the intersection of the two equations, we substitute \( y = 76 \) into the second equation, resulting in the equation \( 76 = x^2 - 5 \). When we solve for \( x \), we rearrange to get \( x^2 = 76 + 5 = 81 \). This gives us \( x = \pm 9 \). So, possible values for \( x \) are \( 9 \) or \( -9 \). The possible value \( -\frac{76}{5} \) is not correct, but it's an interesting number! In converting it to a decimal, it becomes approximately -15.2, an example of how calculations can lead to very different ideas when we miss the right path! Remember, handling equations can be an adventure, and sometimes small mistakes lead to curious results! Always double-check to ensure you're on the right track and understand how the equations relate to each other!

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