5. At $$ x=3 $$, the function given by $$ f(x)=\left\{\begin{array}{ll}x^{2}, & x

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5. At $$ x=3 $$, the function given by $$ f(x)=\left\{\begin{array}{ll}x^{2}, & x<3 \ 6 x-9, & x \geq 3\end{array}ight. $$ is

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It seems that there is an issue with calculating the value of $$ f(3) $$ directly. Let's break down the function $$ f(x) $$ into two parts based on the given conditions:

For $$ x < 3 $$, $$ f(x) = x^2 $$

For $$ x \geq 3 $$, $$ f(x) = 6x - 9 $$

Now, we can calculate $$ f(3) $$ using the appropriate part of the function:

For $$ x = 3 $$, since $$ x \geq 3 $$, we use the second part of the function: $$ f(3) = 6(3) - 9 $$

Let's calculate this:
Calculate the value by following steps:
- step0: Calculate:
  $$6	imes 3-9$$
- step1: Multiply the numbers:
  $$18-9$$
- step2: Subtract the numbers:
  $$9$$
Therefore, $$ f(3) = 9 $$.
当 $$ x = 3 $$ 时，函数 $$ f(x) = \begin{cases} x^2, & x < 3 \ 6x - 9, & x \geq 3 \end{cases} $$ 的值为 9。

At , the function given by is

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