11. Point \( X \) is at \( \frac{2}{3} \) on a number line. On the same number line, point \( Y \) is the same distance from 0 as point \( X \), but it has a numerator of 8 . What is the denominator of the fraction at point \( Y \) ? Draw a number
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Point \( Y \) is determined by maintaining the same distance from 0 as point \( X \) at \( \frac{2}{3} \). Since the distance from 0 to point \( X \) is \( \frac{2}{3} \), point \( Y \) must also be \( \frac{8}{d} \) where \( d \) is its unknown denominator. Setting the two distances equal \( \frac{8}{d} = \frac{2}{3} \), we can cross-multiply to find \( 8 \cdot 3 = 2 \cdot d \), yielding \( d = 12 \). Thus, point \( Y \) is at \( \frac{8}{12} \) or simplified, \( \frac{2}{3} \). To visualize this, imagine a number line where 0 is in the center. Point \( X \) is to the right at \( \frac{2}{3} \), and point \( Y \) reflects the same distance away from 0 but on the left side with a fraction of \( \frac{8}{12} \). Both points are actually equal distances from the center!