Use properties of logarithms to find the exact value of the expression. Do not use a calculator. $$ \log _{16} 2+\log _{16} 8 $$

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To find the exact value of the expression $$\log_{16} 2 + \log_{16} 8$$ using properties of logarithms, follow these steps:

1. **Use the Product Property of Logarithms**:
   The product property states that $$\log_b (M) + \log_b (N) = \log_b (MN)$$. Applying this property:
   $$
   \log_{16} 2 + \log_{16} 8 = \log_{16} (2 \times 8) = \log_{16} 16
   $$

2. **Evaluate the Logarithm**:
   Since $$16$$ is the base of the logarithm, $$\log_{16} 16$$ asks, "To what power must $$16$$ be raised to get $$16$$?" The answer is $$1$$:
   $$
   \log_{16} 16 = 1
   $$

Therefore, the exact value of the expression is:

**Answer:** $$1$$
The exact value of the expression is $$1$$.

Use properties of logarithms to find the exact value of the expression. Do not use a calculator.

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