Question
Solve the equation \( \log _{6}(13-x)=1 \) \( x=\square \) DONE
Ask by Edwards Munoz. in the United States
Jan 23,2025
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Answer
\( x = 7 \)
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To solve the equation \( \log _{6}(13-x)=1 \), we can rewrite it in exponential form. This means \( 13 - x = 6^1 \). Since \( 6^1 = 6 \), we have: \[ 13 - x = 6 \] Now, solving for \( x \) gives: \[ x = 13 - 6 = 7 \] Thus, \( x = 7 \). x=7