Given the velocity function \( v \) of an object moving along a line, explain how definite integrals can be used \( t 0 \) find the displacement of the object. Choose the correct answer below. A. The displacement between \( t=a \) and \( t=b,[a, b] \), is \( \int_{a}^{b} v(t) d t \). The displacement between \( t=a \) and \( t=b,[a, b] \), is \( \int_{a}^{b}|v(t)| d t \). C. The displacement between \( t=a \) and \( t=b,[a, b] \), is \( \int_{b}^{a} v(t) d t \). D. The displacement between \( t=a \) and \( t=b,[a, b] \), is \( \int_{b}^{a}|v(t)| d t \).
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The displacement of an object moving along a line can be determined by evaluating the definite integral of its velocity function over a given interval. Specifically, the displacement between \( t=a \) and \( t=b \) is calculated as \( \int_{a}^{b} v(t) \, dt \). This integral sums up all the instantaneous velocities over the time interval, providing a net change in position. For clarity, remember that if the velocity function \( v(t) \) takes negative values during the interval, it indicates that the object is moving in the opposite direction. Therefore, while the integral \( \int_{a}^{b} v(t) \, dt \) gives you the net displacement, \( \int_{a}^{b} |v(t)| \, dt \) would provide the total distance traveled regardless of direction. So, the right answer here is \( A \), emphasizing the net change in position with consideration of the velocity's sign.