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0. A cube has an edge length of 5 cm . How many times greater will the volume be for a different cub with double the edge lengths? (show your work)

Ask by Pope Mcdonald. in Canada
Jan 22,2025

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Answer

The volume of the second cube is 8 times greater than the original cube.

Solution

To determine how many times greater the volume of the second cube is compared to the first cube, follow these steps: 1. **Understand the Volume Formula for a Cube:** The volume \( V \) of a cube with edge length \( a \) is given by: \[ V = a^3 \] 2. **Calculate the Volume of the Original Cube:** - **Edge Length (\( a_1 \)):** 5 cm - **Volume (\( V_1 \)):** \[ V_1 = a_1^3 = 5^3 = 125 \text{ cm}^3 \] 3. **Determine the Edge Length of the Second Cube:** The second cube has double the edge length of the first cube. \[ a_2 = 2 \times a_1 = 2 \times 5 \text{ cm} = 10 \text{ cm} \] 4. **Calculate the Volume of the Second Cube:** - **Volume (\( V_2 \)):** \[ V_2 = a_2^3 = 10^3 = 1000 \text{ cm}^3 \] 5. **Find How Many Times Greater the Second Volume Is:** \[ \text{Ratio} = \frac{V_2}{V_1} = \frac{1000}{125} = 8 \] **Conclusion:** The volume of the second cube is **8 times greater** than the volume of the original cube.

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To find the volume of a cube, you use the formula \( V = s^3 \), where \( s \) is the edge length. For the first cube with an edge length of 5 cm: \[ V_1 = 5^3 = 125 \text{ cm}^3 \] For the second cube with double the edge length (10 cm): \[ V_2 = 10^3 = 1000 \text{ cm}^3 \] Now, to find how many times greater the volume of the second cube is than the first cube: \[ \text{Times greater} = \frac{V_2}{V_1} = \frac{1000}{125} = 8 \] So, the volume of the second cube is 8 times greater than the first cube.

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