Question

11. Always, Sometimes, or Never? a. A, S , or \( \mathrm{N}: \) A 4th degree polynomial can have 2 real roots. b. \( \mathrm{A}, \mathrm{S} \), or \( \mathrm{N}: \) If \( \mathrm{P}(3)=\mathrm{P}(-5)=0 \), then \( \mathrm{P}(\text{x})=\text{x}^{2}+2 \text{x}-15 \).

Ask by Rodriquez Cruz. in the United States
Jan 22,2025

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Tutor-Verified Answer

Answer

a. Sometimes (S) b. Never (N)

Solution

Let's analyze each statement: ### a. A 4th degree polynomial can have 2 real roots. - **Answer:** **Sometimes (S)** A fourth-degree polynomial can have up to four real roots. It **can** have exactly two real roots (with the other two being complex), but this is not always the case. Therefore, it is **sometimes** possible. ### b. If \( \mathrm{P}(3)=\mathrm{P}(-5)=0 \), then \( \mathrm{P}(\text{x})=\text{x}^{2}+2 \text{x}-15 \). - **Answer:** **Never (N)** If \( \mathrm{P}(3) = 0 \) and \( \mathrm{P}(-5) = 0 \), it means that \( \mathrm{P}(x) \) has factors \( (x - 3) \) and \( (x + 5) \). However, this does **not** necessarily imply that \( \mathrm{P}(x) \) is exactly \( x^{2} + 2x - 15 \). The polynomial could be of higher degree or have additional factors. Therefore, the statement is **never** necessarily true. **Summary of Answers:** - **a. Sometimes (S)** - **b. Never (N)**

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Extra Insights

A 4th degree polynomial can indeed have 2 real roots, but it can also have 0, 1, 3, or 4 real roots depending on its behavior, so the answer is sometimes! Polynomials can change their number of real roots due to factors like complex roots or multiplicities, which adds some excitement to their analysis. On the other hand, the equation \( P(x) = x^2 + 2x - 15 \) has roots at \( x = 3 \) and \( x = -5 \), but that means it can be factored as \( P(x) = (x - 3)(x + 5) \) and doesn't fully express that \( P \) could also have higher degree terms. So again, here the answer is sometimes! Understanding both polynomial equations and their factorization gives insights into the rich world of algebra.

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