(2) \( 3 \cdot 5^{x}+5^{x+1}=40 \)
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To solve the equation \( 3 \cdot 5^{x} + 5^{x+1} = 40 \), first notice that \( 5^{x+1} = 5 \cdot 5^{x} \). You can rewrite the equation as \( 3 \cdot 5^{x} + 5 \cdot 5^{x} = 40 \). This simplifies to \( (3 + 5) \cdot 5^{x} = 40 \), or \( 8 \cdot 5^{x} = 40 \). Dividing both sides by 8 gives \( 5^{x} = 5 \), which implies \( x = 1 \). If you want to check your solution, substitute \( x = 1 \) back into the original equation: \[ 3 \cdot 5^{1} + 5^{2} = 3 \cdot 5 + 25 = 15 + 25 = 40. \] The equation holds true, confirming that \( x = 1 \) is indeed the correct solution! Happy solving!