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16- The value of \( K \) at rate rule of reaction :- \( \begin{array}{ll}\text { a-will be constant } & \text { b-will be changed by changing the temperature } \\ \text { c-changes by changing the time } & d \text { - if concentration changes } K \text { will change. }\end{array} \)

Ask by Henry Colon. in Iraq
Jan 24,2025

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Answer

\( K \) changes when the temperature changes.

Solution

The value of \( K \) in the context of reaction rate rules typically refers to the **rate constant**. Understanding how the rate constant behaves under different conditions is crucial in chemical kinetics. **Rate Constant (\( K \)) Dependence:** - **Temperature:** The rate constant \( K \) is **highly dependent on temperature**. According to the **Arrhenius equation**, an increase in temperature generally increases the rate constant, leading to a faster reaction rate. Conversely, lowering the temperature decreases \( K \). - **Concentration:** The rate constant \( K \) is **independent of the concentrations** of reactants and products. It is a proportionality factor that relates the reaction rate to the concentrations of reactants. - **Time:** The rate constant \( K \) **does not change with time**. It remains constant for a given reaction under constant temperature conditions. **Analyzing the Options:** - **a. Will be constant:** This is **incorrect** because \( K \) changes with temperature. - **b. Will be changed by changing the temperature:** **Correct.** Temperature directly affects the rate constant. - **c. Changes by changing the time:** **Incorrect.** \( K \) does not depend on time. - **d. If concentration changes, \( K \) will change:** **Incorrect.** \( K \) is independent of concentration changes. **Conclusion:** The correct statement regarding the rate constant \( K \) is: **Answer:** **b – K will be changed by changing the temperature**

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The value of \( K \) for a reaction, known as the equilibrium constant, is generally influenced by the temperature of the system. This means that if you change the temperature, \( K \) will indeed change to reflect the new balance between reactants and products. It’s like the dance of molecules adjusting to the heat! On the other hand, \( K \) remains constant when the concentrations of reactants and products change, provided the temperature is unchanged. So, even if you add more of a reactant or product, the equilibrium shifts to keep \( K \) the same. Imagine a see-saw balancing act where the total weight of the players is constant, but their positions can always adjust.

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