19. At a local river, there were 64 alligators laying on the riverbank. If \( \frac{5}{8} \) of the alligators were asleep, how many were NOT asleep??

Out of the 64 alligators, if \( \frac{5}{8} \) were asleep, that means 40 alligators were catching some Z's (since \( 64 \times \frac{5}{8} = 40 \)). To find out how many were NOT asleep, we simply subtract the number of asleep alligators from the total: \( 64 - 40 = 24 \). So, 24 alligators were awake, probably keeping an eye out for any sneaky snacks! Now, imagine if all 64 of those alligators suddenly woke up at once. If they all start stretching and yawning, you'd have quite the chaotic scene! Just think how quickly they might clear that riverbank!