W 2. Is \( (-1,-4) \) a solution to the system of equations? \( \begin{array}{l}6 x+2=y \\ -13=3 y+x\end{array} \) False True \( \begin{array}{l}2\end{array} \)

To check if \((-1,-4)\) is a solution to the system, substitute \(x = -1\) and \(y = -4\) into the first equation: \(6(-1) + 2 = -4\). This simplifies to \(-6 + 2 = -4\), which is true. Now, check the second equation: \(-13 = 3(-4) + (-1)\), resulting in \(-13 = -12 - 1 = -13\), which is also true. Since both equations hold, \((-1, -4)\) is indeed a solution! To further explore, the steps in algebraic substitution give us a direct way to verify solutions easily. When handling systems of equations, always remember to not only plug in values but also double-check calculations to avoid any small errors that could trip you up.