Question

In rhombus \( A B C D \), the diagonals \( \overline{A C} \) and \( \overline{B D} \) intersect at \( E \). If \( A E=5 \) and \( B E=12 \), what is the length of \( \overline{A B} \) ? 1) 7 2) 10 3) 13 4) 17

Ask by Mann Vaughan. in China
Jan 23,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

边长 \( \overline{A B} \) 的长度是 13。

Solution

在菱形 \( A B C D \) 中,两个对角线 \( \overline{A C} \) 和 \( \overline{B D} \) 相交于点 \( E \),并且互相垂直。已知 \( A E = 5 \) 和 \( B E = 12 \),则: 1. 对角线 \( \overline{A C} = 2 \times A E = 2 \times 5 = 10 \) 2. 对角线 \( \overline{B D} = 2 \times B E = 2 \times 12 = 24 \) 在菱形中,边长可以通过对角线的半长使用勾股定理计算: \[ AB = \sqrt{\left(\frac{AC}{2}\right)^2 + \left(\frac{BD}{2}\right)^2} = \sqrt{5^2 + 12^2} = \sqrt{25 + 144} = \sqrt{169} = 13 \] 因此,边长 \( \overline{A B} \) 的长度是 **13**。 **答案选项:3) 13**

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The Deep Dive

In rhombus \( A B C D \), the diagonals bisect each other at right angles. This means that \( E \) is the midpoint of both diagonals \( \overline{A C} \) and \( \overline{B D} \). Given \( A E = 5 \) and \( B E = 12 \), we can find the lengths of the sides of the rhombus using the Pythagorean theorem: Let the sides of the rhombus be represented as \( AB = s \). Since diagonals bisect each other, triangle \( ABE \) is a right triangle where \( A E \) and \( B E \) are the legs. Thus, we can use the formula: \[ AB = \sqrt{(AE)^2 + (BE)^2} = \sqrt{(5)^2 + (12)^2} = \sqrt{25 + 144} = \sqrt{169} = 13. \] Therefore, the length of \( \overline{A B} \) is \( 13 \). The correct answer is option 3) 13.

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