c) \( \frac{9^{x}-9}{3^{x}-3} \)
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Bonus Knowledge
To simplify the expression \( \frac{9^{x}-9}{3^{x}-3} \), notice that \( 9 \) can be rewritten as \( 3^2 \). Therefore, we can express \( 9^x \) as \( (3^2)^x = 3^{2x} \). Substituting this into the equation gives us: \[ \frac{3^{2x} - 9}{3^x - 3} \] Next, we can factor \( 9 \) out of the numerator: \[ 9 = 3^2 \implies \frac{3^{2x} - 3^2}{3^x - 3} \] Now, recognize that \( 3^{2x} - 3^2 \) can be factored using the difference of squares: \[ 3^{2x} - 3^2 = (3^x - 3)(3^x + 3) \] Thus, we can rewrite the expression as: \[ \frac{(3^x - 3)(3^x + 3)}{3^x - 3} \] For \( x \neq 1 \) (to avoid division by zero), we can cancel out \( 3^x - 3 \): \[ 3^x + 3 \] Therefore, the simplified expression is: \[ 3^x + 3 \] This effectively reduces the original expression to a much simpler form, \( 3^x + 3 \).