Question
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Ising the rational root theorem, list out all possible/candidate rational roots of \( (x)=5 x^{4}-x^{2}-14 x+6 \). Express your answer as integers or as fractions in simplest form. Use ommas to separate.

Ask by Ray Elliott. in the United States
Jan 23,2025

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Tutor-Verified Answer

Answer

The possible rational roots are: -6, -3, -2, -1, -6/5, -3/5, -2/5, -1/5, 1/5, 2/5, 3/5, 6/5, 1, 2, 3, 6

Solution

The possible rational roots of the polynomial \( p(x) = 5x^{4} - x^{2} - 14x + 6 \) using the Rational Root Theorem are: \[ -6, -3, -2, -1, -\frac{6}{5}, -\frac{3}{5}, -\frac{2}{5}, -\frac{1}{5}, \frac{1}{5}, \frac{2}{5}, \frac{3}{5}, \frac{6}{5}, 1, 2, 3, 6 \] **Answer:** -6,-3,-2,-1,-6/5,-3/5,-2/5,-1/5,1/5,2/5,3/5,6/5,1,2,3,6

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Extra Insights

To find the possible rational roots of the polynomial \( f(x) = 5x^4 - x^2 - 14x + 6 \) using the Rational Root Theorem, we first identify the constant term (6) and the leading coefficient (5). The candidates for rational roots can be expressed as: \[ \frac{p}{q} \] where \( p \) is a factor of the constant term (6) and \( q \) is a factor of the leading coefficient (5). The factors of 6 are \( \pm 1, \pm 2, \pm 3, \pm 6 \), and the factors of 5 are \( \pm 1, \pm 5 \). Thus, the possible rational roots are: \[ \pm 1, \pm 2, \pm 3, \pm 6, \pm \frac{1}{5}, \pm \frac{2}{5}, \pm \frac{3}{5}, \pm \frac{6}{5} \]

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