Question
Solve this linear equation: \( \quad 0 r-3=3 x+15 \)
Ask by Allan Elliott. in Qatar
Jan 26,2025
Real Tutor Solution
Tutor-Verified Answer
Answer
\( x = -6 \)
Solution
Let's solve the linear equation:
\[
0 \cdot r - 3 = 3x + 15
\]
**Step 1: Simplify the Equation**
First, simplify the left side of the equation:
\[
0 \cdot r - 3 = -3
\]
So the equation becomes:
\[
-3 = 3x + 15
\]
**Step 2: Isolate the Variable Term**
Subtract 15 from both sides to isolate the term with \( x \):
\[
-3 - 15 = 3x
\]
\[
-18 = 3x
\]
**Step 3: Solve for \( x \)**
Divide both sides by 3 to solve for \( x \):
\[
x = \frac{-18}{3} = -6
\]
**Solution:**
\[
x = -6
\]
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Mind Expander
To solve the equation \( 0r - 3 = 3x + 15 \), we first notice that \( 0r \) simplifies to just \( 0 \). Thus, the equation becomes: \[ -3 = 3x + 15 \] Next, we can isolate \( 3x \) by adding \( 3 \) to both sides: \[ -3 + 3 = 3x + 15 + 3 \] \[ 0 = 3x + 18 \] Now, let's subtract \( 18 \) from both sides: \[ 0 - 18 = 3x \] \[ -18 = 3x \] Finally, divide both sides by \( 3 \) to solve for \( x \): \[ x = -6 \] So, the solution to the linear equation is \( x = -6 \).