Question
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Solve this linear equation: \( \quad 0 r-3=3 x+15 \)

Ask by Allan Elliott. in Qatar
Jan 26,2025

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Tutor-Verified Answer

Answer

\( x = -6 \)

Solution

Let's solve the linear equation: \[ 0 \cdot r - 3 = 3x + 15 \] **Step 1: Simplify the Equation** First, simplify the left side of the equation: \[ 0 \cdot r - 3 = -3 \] So the equation becomes: \[ -3 = 3x + 15 \] **Step 2: Isolate the Variable Term** Subtract 15 from both sides to isolate the term with \( x \): \[ -3 - 15 = 3x \] \[ -18 = 3x \] **Step 3: Solve for \( x \)** Divide both sides by 3 to solve for \( x \): \[ x = \frac{-18}{3} = -6 \] **Solution:** \[ x = -6 \]

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Mind Expander

To solve the equation \( 0r - 3 = 3x + 15 \), we first notice that \( 0r \) simplifies to just \( 0 \). Thus, the equation becomes: \[ -3 = 3x + 15 \] Next, we can isolate \( 3x \) by adding \( 3 \) to both sides: \[ -3 + 3 = 3x + 15 + 3 \] \[ 0 = 3x + 18 \] Now, let's subtract \( 18 \) from both sides: \[ 0 - 18 = 3x \] \[ -18 = 3x \] Finally, divide both sides by \( 3 \) to solve for \( x \): \[ x = -6 \] So, the solution to the linear equation is \( x = -6 \).

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