Question 6 Suppose an account pays \( 5 \% \) interest that is compounded annually. At the beginning of each year, \( \$ 1,000 \) is deposited into the account (starting with \( \$ 1,000 \) for the first year). How much money is in the account at the end of the tenth year if no withdrawals or additional deposits are made?
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To calculate the total amount in the account at the end of the tenth year, we'll use the formula for the future value of a series of annuities due to the annual deposits. Each deposit earns interest for a different number of years. 1. The first deposit of \$1,000 will earn interest for 10 years. 2. The second deposit of \$1,000 will earn interest for 9 years. 3. This pattern continues until the last deposit, which will earn interest for just 1 year. The formula for the future value of a single sum is: \[ FV = P(1 + r)^n \] Where \( P \) is the principal, \( r \) is the interest rate, and \( n \) is the number of years. Now, let’s sum it up: - Amount from the first deposit (10 years): \[ \$ 1,000 \times (1 + 0.05)^{10} \approx \$ 1,628.89 \] - Amount from the second deposit (9 years): \[ \$ 1,000 \times (1 + 0.05)^{9} \approx \$ 1,498.31 \] - Amount from the third deposit (8 years): \[ \$ 1,000 \times (1 + 0.05)^{8} \approx \$ 1,386.62 \] Continue this calculation down to the last deposit, and you’ll sum all the future values of each year's deposits. Finally, the total amount after 10 years is approximately: \[ \$ 1,628.89 + \$ 1,498.31 + \$ 1,386.62 + \$ 1,278.58 + \$ 1,182.04 + \$ 1,086.08 + \$ 1,000.00 + \$ 918.37 + \$ 846.12 + \$ 1,000.00 \approx \$ 16,253.76 \] So, you will have about \$16,253.76 in the account at the end of the tenth year! Happy saving!