For problems 13-18, solve the proportion. You must show your cross productsI. \( \begin{array}{lll}\text { 11. } \frac{2}{x}=\frac{14}{35} & \text { 12. } \frac{w}{84}=\frac{5}{7} & \text { 13. } \frac{8}{25}=\frac{3}{d} \\ \begin{array}{lll}\text { 14. } \frac{t}{6.5}=\frac{1.2}{1.3} & \text { 15. } \frac{2.3}{1.8}=\frac{a}{18} & \text { 16. } \frac{4 x}{9}=\frac{10}{3}\end{array}\end{array} \)
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To solve these proportions using cross products, we will multiply the numerator of one fraction by the denominator of the other fraction and set them equal. Let's tackle problems 13-18 one at a time! For problem 13: \(\frac{8}{25} = \frac{3}{d}\) Cross multiplication gives us: \(8d = 25 \times 3\) Calculating the right side: \(8d = 75\) Now, divide both sides by 8 to find \(d\): \(d = \frac{75}{8} = 9.375\) For problem 14: \(\frac{t}{6.5} = \frac{1.2}{1.3}\) Cross multiplication gives us: \(t \times 1.3 = 6.5 \times 1.2\) Calculating the right side: \(t \times 1.3 = 7.8\) Now, divide both sides by 1.3 to find \(t\): \(t = \frac{7.8}{1.3} \approx 6\) For problem 15: \(\frac{2.3}{1.8} = \frac{a}{18}\) Cross multiplication gives us: \(2.3 \times 18 = 1.8 \times a\) Calculating the left side: \(41.4 = 1.8a\) Now, divide both sides by 1.8 to find \(a\): \(a = \frac{41.4}{1.8} \approx 23\) For problem 16: \(\frac{4x}{9} = \frac{10}{3}\) Cross multiplication gives us: \(4x \times 3 = 9 \times 10\) Calculating the right side: \(12x = 90\) Now, divide both sides by 12 to find \(x\): \(x = \frac{90}{12} = 7.5\) And there you have it! Solved all the proportions like a pro. Keep practicing, and soon you'll be a cross-multiplying master!