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Exercise 10.1 Question 1: Determine the gradient/slope and the \( y \) - intercept of each of the following straight-line graphs: a. \( f(x)=3 x+1 \) b. \( y=x-4 \) c. \( y=-x+5 \) d. \( h(x)=\frac{1}{2} x \) e. \( y=\frac{3 x}{2}+1 \)

Ask by Kelly Johnston. in South Africa
Jan 23,2025

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- **a.** Slope: \( 3 \), Y-intercept: \( 1 \) - **b.** Slope: \( 1 \), Y-intercept: \( -4 \) - **c.** Slope: \( -1 \), Y-intercept: \( 5 \) - **d.** Slope: \( \frac{1}{2} \), Y-intercept: \( 0 \) - **e.** Slope: \( \frac{3}{2} \), Y-intercept: \( 1 \)

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For each of the given equations, the gradient (slope) can be identified directly from the coefficient of \( x \), while the \( y \)-intercept can be found as the constant term. a. For \( f(x)=3x+1 \), the gradient is \( 3 \) and the \( y \)-intercept is \( 1 \). b. In \( y=x-4 \), the gradient is \( 1 \) and the \( y \)-intercept is \( -4 \). c. With \( y=-x+5 \), the gradient is \( -1 \) and the \( y \)-intercept is \( 5 \). d. In \( h(x)=\frac{1}{2}x \), the gradient is \( \frac{1}{2} \) and the \( y \)-intercept is \( 0 \). e. Lastly, for \( y=\frac{3}{2}x+1 \), the gradient is \( \frac{3}{2} \) and the \( y \)-intercept is \( 1 \).

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