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If ABCD is dilated by a factor of 2, the coordinate of \( \mathrm{B}^{\prime} \) would be: \( \mathrm{B}^{\prime}=([?],[]) \)

Ask by Todd Coles. in the United States
Jan 02,2025

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Answer

To find the coordinates of \( \mathrm{B}^{\prime} \) after a dilation by a factor of 2, you need the original coordinates of point B. Once you have \( (x_B, y_B) \), multiply each by 2 to get \( \mathrm{B}^{\prime} = (2x_B, 2y_B) \).

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Bonus Knowledge

When a point is dilated from the origin by a factor of 2, both its x and y coordinates are multiplied by 2. So, if we assume the coordinates of \( \mathrm{B} \) are \( (x_B, y_B) \), then the coordinates of \( \mathrm{B}^{\prime} \) after dilation become \( \mathrm{B}^{\prime} = (2 \cdot x_B, 2 \cdot y_B) \). To find \( \mathrm{B}^{\prime} \) specifically, you'll need to plug in the actual coordinates of point \( \mathrm{B} \). If \( \mathrm{B} \) was at \( (3, 4) \), for example, then \( \mathrm{B}^{\prime} \) would be \( (6, 8) \). Just multiply the original coordinates by 2 to get \( \mathrm{B}^{\prime} \).

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