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Is this statement true or false? In a regular polygon, two consecutive radii and their included side form an equilateral triangle. false true

Ask by Flynn Burgess. in the United States
Jan 24,2025

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Answer

The statement is **false** because it only holds true for a regular hexagon, not for all regular polygons.

Solution

**False.** In a regular polygon, the statement that two consecutive radii and their included side form an equilateral triangle holds true **only** for a regular hexagon. Here's why: - **Regular Hexagon (6 sides):** - Each central angle is 60 degrees. - The length of each side is equal to the radius (\( R \)) of the circumscribed circle. - Therefore, the triangle formed by two consecutive radii and the included side is equilateral. - **Other Regular Polygons:** - For polygons with a different number of sides (e.g., equilateral triangle with 3 sides, square with 4 sides, etc.), the relation does not hold. - For instance, in a square (4 sides), the side length is \( \sqrt{2}R \), which is not equal to the radius \( R \), making the triangle isosceles but not equilateral. Since the statement is not universally true for all regular polygons, it is **false**.

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In a regular polygon, the statement is actually false. While two consecutive radii do indeed form equal angles with the center of the polygon, they do not automatically create an equilateral triangle with the included side unless the polygon is specifically an equilateral triangle itself. For example, in a regular hexagon, the included side is shorter than the two radii, leading to an isosceles triangle instead! Now, if you're ever in a geometry bind, remember to visualize the scenario! Draw a sketch of the polygon and label the radii and sides. This will help you see the relationships and clarify any confusion about angles and side lengths. Don't forget: a common mistake is assuming measurements are equal without validating it through geometric principles!

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